What is the inverse of f(x)=x^2+7x ?

The inverse of f(x)=x^2+7x is (-7+sqrt(49+4x))/2 ,(-7-sqrt(49+4x))/2

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inverse of f(x)=x^2+7x

inverse

f (x) = x^{2} + 7 x

\frac{- 7 + 49 + 4 x}{2}, \frac{- 7 - 49 + 4 x}{2}

Solution steps

y = x^{2} + 7 x

Replace

x

with

y

x = y^{2} + 7 y

Solve for

y, x = y^{2} + 7 y

\frac{- 7 + 49 + 4 x}{2}, \frac{- 7 - 49 + 4 x}{2}

f (x) = \frac{x + 1}{x ^{2} - 3 x + 2}

7 x + 3 y = 9

9 x - y = 9, (8, 6)

1

f (x) = \frac{( 4 - 2 x )}{( 3 x - 1 )}

What is the inverse of f(x)=x^2+7x ?
The inverse of f(x)=x^2+7x is (-7+sqrt(49+4x))/2 ,(-7-sqrt(49+4x))/2