What is the domain of sqrt(5-x)+sqrt(x^2-4) ?

The domain of sqrt(5-x)+sqrt(x^2-4) is x<=-2\lor 2<= x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(5-x)+sqrt(x^2-4)

domain

5 - x + x^{2} - 4

x \leq - 2 or 2 \leq x \leq 5

Interval Notation

(- \infty, - 2] \cup [2, 5]

Solution steps

Find non-negative values for radicals:

x \leq - 2 or 2 \leq x \leq 5

The function domain

x \leq - 2 or 2 \leq x \leq 5

f (x) = \frac{x ^{2} + 5 x - 3}{4 x - 1}

f (x) = π

(x - 2)^{2} + 3

2 x^{6} - 3 x^{5}

f (x) = \frac{1}{( x + 10 )}

What is the domain of sqrt(5-x)+sqrt(x^2-4) ?
The domain of sqrt(5-x)+sqrt(x^2-4) is x<=-2\lor 2<= x<= 5