What is the asymptotes of f(x)=(x^2+6x)/(2x-12) ?

The asymptotes of f(x)=(x^2+6x)/(2x-12) is Vertical: x=6,Slant: y= 1/2 x+6

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asymptotes of f(x)=(x^2+6x)/(2x-12)

asymptotes

f (x) = \frac{x ^{2} + 6 x}{2 x - 12}

Vertical : x = 6, Slant : y = \frac{1}{2} x + 6

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 6 x}{2 x - 12} : x = 6

Horizontal Asymptotes of

\frac{x ^{2} + 6 x}{2 x - 12} :

None

Slant Asymptotes of

\frac{x ^{2} + 6 x}{2 x - 12} : y = \frac{1}{2} x + 6

Vertical : x = 6, Slant : y = \frac{1}{2} x + 6

y = x + \frac{4}{x}

1 - x^{2}

f (x) = - x^{3} + 5 x^{2} + 8 x - 3

f (x) = 3^{x} - 5

cos (3 x)

What is the asymptotes of f(x)=(x^2+6x)/(2x-12) ?
The asymptotes of f(x)=(x^2+6x)/(2x-12) is Vertical: x=6,Slant: y= 1/2 x+6