What is the asymptotes of f(x)=(x^2-4)/(x^2-3x+2) ?

The asymptotes of f(x)=(x^2-4)/(x^2-3x+2) is Vertical: x=1,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-4)/(x^2-3x+2)

asymptotes

f (x) = \frac{x ^{2} - 4}{x ^{2} - 3 x + 2}

Vertical : x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 3 x + 2} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 3 x + 2} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 3 x + 2} :

None

Vertical : x = 1, Horizontal : y = 1

(5, 2), (- 6, - 3)

f (x) = (x + 5)^{\frac{4}{5}}

- \frac{1}{5} 3^{x} - 2

f (x) = \frac{10 x ^{2}}{5 x ^{2} + 2}

f (x) = \frac{2}{3 - x}

What is the asymptotes of f(x)=(x^2-4)/(x^2-3x+2) ?
The asymptotes of f(x)=(x^2-4)/(x^2-3x+2) is Vertical: x=1,Horizontal: y=1