What is the domain of f(x)=sqrt(2x-62) ?

The domain of f(x)=sqrt(2x-62) is x>= 31

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domain of f(x)=sqrt(2x-62)

domain

f (x) = 2 x - 62

x \geq 31

Interval Notation

[31, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 31

The function domain

x \geq 31

f (x) = x^{2} + 2 x - 5

f (x) = \frac{2 x + 5}{2 x - 16}

3^{x} - 2^{x}

x^{2} - 8 x + 7

- x + 4

What is the domain of f(x)=sqrt(2x-62) ?
The domain of f(x)=sqrt(2x-62) is x>= 31