What is the inverse of f(x)=((x+1))/((4x+1)) ?

The inverse of f(x)=((x+1))/((4x+1)) is (1-x)/(4x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x+1))/((4x+1))

inverse

f (x) = \frac{( x + 1 )}{( 4 x + 1 )}

\frac{1 - x}{4 x - 1}

Solution steps

y = \frac{x + 1}{4 x + 1}

Replace

x

with

y

x = \frac{y + 1}{4 y + 1}

Solve for

y, x = \frac{y + 1}{4 y + 1}

\frac{1 - x}{4 x - 1}

e^{- 0.5 x^{2}}

f (x) = 4 x^{2} + 1

f (x) = \frac{3 x + 4}{5 - 4 x}

x - 4 = 0

f (x) = x^{3} - 1

What is the inverse of f(x)=((x+1))/((4x+1)) ?
The inverse of f(x)=((x+1))/((4x+1)) is (1-x)/(4x-1)