What is the perpendicular y=x,(6,1) ?

The perpendicular y=x,(6,1) is y=-x+7

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perpendicular y=x,(6,1)

perpendicular

y = x, (6, 1)

y = - x + 7

Solution steps

Find the line

y = mx + b

perpendicular to

y = x

that passes through

(6, 1)

Find the slope of

y = x : m = 1

Compute the slope of the perpendicular line:

m_{p} = - 1

Find the line with slope m=

- 1

and passing through

(6, 1) : y = - x + 7

y = - x + 7

f (x) = 3 y + 2 x = - x + 5

f (x) = (\frac{2 x}{x + 2})

\frac{x ^{3}}{x ^{2} + 3 x - 10}

f (x) = \frac{6}{- 3 x + 2}

f (x) = \frac{3}{( x ^{2} + 3 x - 40 )}