What is the domain of f(x)= 6/(x+4)+1/(2-x) ?

The domain of f(x)= 6/(x+4)+1/(2-x) is x 2

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domain of f(x)= 6/(x+4)+1/(2-x)

domain

f (x) = \frac{6}{x + 4} + \frac{1}{2 - x}

x < - 4 or - 4 < x < 2 or x > 2

Interval Notation

(- \infty, - 4) \cup (- 4, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = 2

The function domain

x < - 4 or - 4 < x < 2 or x > 2

f (x) = - 6 6 - x^{2} + 2

(- 1, - 2), (- 2, 3)

y = 2 x^{2} + 4

\frac{5 - 3 x}{2}

6 tan (0.2 x)

What is the domain of f(x)= 6/(x+4)+1/(2-x) ?
The domain of f(x)= 6/(x+4)+1/(2-x) is x<-4\lor-4<x<2\lor x>2