What is the inverse of f(x)=12(x-3)^2-4 ?

The inverse of f(x)=12(x-3)^2-4 is (sqrt(3)sqrt(x+4))/6+3,-(sqrt(3)sqrt(x+4))/6+3

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inverse of f(x)=12(x-3)^2-4

inverse

f (x) = 12 (x - 3)^{2} - 4

\frac{3 x + 4}{6} + 3, - \frac{3 x + 4}{6} + 3

Solution steps

y = 12 (x - 3)^{2} - 4

Replace

x

with

y

x = 12 (y - 3)^{2} - 4

Solve for

y, x = 12 (y - 3)^{2} - 4

\frac{3 x + 4}{6} + 3, - \frac{3 x + 4}{6} + 3

cot (x) d x

f (x) = \frac{x}{x ^{2} - 3 x - 4}

f (x) = \frac{( x + 3 )}{( x - 5 )}

3 y = 3 x + 6

(1, - 1), (- 10, 2)

What is the inverse of f(x)=12(x-3)^2-4 ?
The inverse of f(x)=12(x-3)^2-4 is (sqrt(3)sqrt(x+4))/6+3,-(sqrt(3)sqrt(x+4))/6+3