What is the domain of f(x)= 1/(sqrt(x+36)) ?

The domain of f(x)= 1/(sqrt(x+36)) is x>-36

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domain of f(x)= 1/(sqrt(x+36))

domain

f (x) = \frac{1}{x + 36}

x > - 36

Interval Notation

(- 36, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 36

Find undefined (singularity) points:

x = - 36

Combine real regions and undefined points for final function domain

x > - 36

(- 1, - 1), (- 7, - 9)

y = - 2 x

f (x) = (x^{2} - 36)^{\frac{1}{3}}

y = x^{2} - 8 x + 12

f (x) = x^{4} - 2 x^{3}

What is the domain of f(x)= 1/(sqrt(x+36)) ?
The domain of f(x)= 1/(sqrt(x+36)) is x>-36