What is the critical (3x)/(4-x^2) ?

The critical (3x)/(4-x^2) is None

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critical (3x)/(4-x^2)

critical points

\frac{3 x}{4 - x ^{2}}

None

Solution steps

\frac{3 x}{4 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x}{4 - x ^{2}} : x < - 2 or - 2 < x < 2 or x > 2

\frac{3 x}{4 - x ^{2}}

is not defined at

x = - 2, x = 2

, therefore:

None

(150, 147.3), (165, 162.7)

f (x) = - x - 3

\frac{2}{t ^{2} - 16}

f (x) = 7 x + 7

2 x - y = 3