What is the domain of f(x)=(sqrt(x+8))/(x-1) ?

The domain of f(x)=(sqrt(x+8))/(x-1) is -8 1

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domain of f(x)=(sqrt(x+8))/(x-1)

domain

f (x) = \frac{x + 8}{x - 1}

- 8 \leq x < 1 or x > 1

Interval Notation

[- 8, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 8 \leq x < 1 or x > 1

\frac{x ^{2} - 1}{x ^{2} + 5 x + 6}

h (x) = \frac{1}{x ^{2} - 1}

sin (7 x)

(11.13) (8.17)

y = 2 cos (2 π (x + \frac{2 π}{3})) - 5

What is the domain of f(x)=(sqrt(x+8))/(x-1) ?
The domain of f(x)=(sqrt(x+8))/(x-1) is -8<= x<1\lor x>1