What is the shift f(t)=cos(1/2 t+pi/3)-pi/6 ?

The shift f(t)=cos(1/2 t+pi/3)-pi/6 is Phase:-(2pi)/3 , Vertical:-pi/6

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shift f(t)=cos(1/2 t+pi/3)-pi/6

shift

f (t) = cos (\frac{1}{2} t + \frac{π}{3}) - \frac{π}{6}

Phase : - \frac{2 π}{3}, Vertical : - \frac{π}{6}

Solution steps

f (x) = cos (\frac{1}{2} t + \frac{π}{3}) - \frac{π}{6}

g (B x - C) = cos (\frac{1}{2} t + \frac{π}{3}), B = \frac{1}{2}, C = - \frac{π}{3}, D = - \frac{π}{6}

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{3}}{\frac{1}{2}}

- \frac{2 π}{3}

The vertical shift

D

- \frac{π}{6}

- \frac{π}{6}

f (x) = csc (x)

ln (e^{x} - 3)

(5.5) - \frac{1}{4}

f (x) = y^{2} = 8 x + 5

(- 2, 0), (1, 1)

What is the shift f(t)=cos(1/2 t+pi/3)-pi/6 ?
The shift f(t)=cos(1/2 t+pi/3)-pi/6 is Phase:-(2pi)/3 , Vertical:-pi/6