What is the inverse of ((7e^x-6))/(e^x+8) ?

The inverse of ((7e^x-6))/(e^x+8) is ln((-6-8x)/(x-7))

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inverse of ((7e^x-6))/(e^x+8)

inverse

\frac{( 7 e ^{x} - 6 )}{e ^{x} + 8}

ln (\frac{- 6 - 8 x}{x - 7})

Solution steps

y = \frac{7 e ^{x} - 6}{e ^{x} + 8}

Replace

x

with

y

x = \frac{7 e ^{y} - 6}{e ^{y} + 8}

Solve for

y, x = \frac{7 e ^{y} - 6}{e ^{y} + 8}

ln (\frac{- 6 - 8 x}{x - 7})

3 x - 5 y = 10

f (x) = 2 x^{2} + 12 x - 2

f (x) = 18500 (0.64 - x^{2})

f (x) = \frac{1}{x}

f (x) = \frac{3}{( 4 - x ^{2} )}

What is the inverse of ((7e^x-6))/(e^x+8) ?
The inverse of ((7e^x-6))/(e^x+8) is ln((-6-8x)/(x-7))