What is the domain of f(x)=sqrt(-x^2+5) ?

The domain of f(x)=sqrt(-x^2+5) is -sqrt(5)<= x<= sqrt(5)

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domain of f(x)=sqrt(-x^2+5)

domain

f (x) = - x^{2} + 5

- 5 \leq x \leq 5

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

The function domain

- 5 \leq x \leq 5

- \frac{9}{2 t ^{\frac{3}{2}}}

f (x) = x^{3} - 12 x

f (x) = - x - 3

f (x) = x^{2} + 2 x + 1

f (x) = \frac{( 5 x - 3 )}{2 x + 5}

What is the domain of f(x)=sqrt(-x^2+5) ?
The domain of f(x)=sqrt(-x^2+5) is -sqrt(5)<= x<= sqrt(5)