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midpoint
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asymptotes of f(x)= 8/(x^2)asymptotes domain of f(x)=\sqrt[3]{-5x}domain domain of f(x)= 4/(x+4)+sqrt(x)+1domain perpendicular y= 1/5 x+4/5perpendicular range of f(x)=sqrt(7-x)range
Frequently Asked Questions (FAQ)
What is the midpoint (2,-7),(-8,6) ?
The midpoint (2,-7),(-8,6) is (-3,-1/2)