What is the critical f(x)=2.2+2.2x-0.6x^2 ?

The critical f(x)=2.2+2.2x-0.6x^2 is x= 11/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=2.2+2.2x-0.6x^2

critical points

f (x) = 2.2 + 2.2 x - 0.6 x^{2}

x = \frac{11}{6}

Solution steps

2.2 + 2.2 x - 0.6 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{11}{6}

Identify critical points not in

f (x)

domain

Domain of

2.2 + 2.2 x - 0.6 x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{11}{6}

f (x) = - 16 t^{2} + 40 t + 3

f (x) = \frac{- 5 x}{3 x + 5}

f (x) = 9

f (x) = \frac{x}{2}

\frac{5}{x + 6}

What is the critical f(x)=2.2+2.2x-0.6x^2 ?
The critical f(x)=2.2+2.2x-0.6x^2 is x= 11/6