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midpoint
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symmetry 4x^2+8x+7symmetry domain of f(x)=2x^2+3x-1domain domain of f(x)=(x-4)/(x+1)domain inverse of sqrt(x-3)+1inverse domain of f(x)=(x-1)/(x^2-4)domain
Frequently Asked Questions (FAQ)
What is the midpoint (2,6),(5,-4) ?
The midpoint (2,6),(5,-4) is (7/2 ,1)