What is the domain of f(x)=sqrt(36-x^2)+sqrt(x+1) ?

The domain of f(x)=sqrt(36-x^2)+sqrt(x+1) is -1<= x<= 6

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domain of f(x)=sqrt(36-x^2)+sqrt(x+1)

domain

f (x) = 36 - x^{2} + x + 1

- 1 \leq x \leq 6

Interval Notation

[- 1, 6]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 6

The function domain

- 1 \leq x \leq 6

(1, 7), (6, - 5)

f (x) = sin (4 x + 2 π)

(- 6, 4), (- 5, - 10)

y = 6 x^{2} + 2 x - 4

f (x) = x^{4} - 7 x^{3} + 6 x^{2} + 19 x + 5

What is the domain of f(x)=sqrt(36-x^2)+sqrt(x+1) ?
The domain of f(x)=sqrt(36-x^2)+sqrt(x+1) is -1<= x<= 6