What is the inflection f(x)=(x+2)^2(x+1) ?

The inflection f(x)=(x+2)^2(x+1) is (-5/3 ,-2/27)

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inflection f(x)=(x+2)^2(x+1)

inflection points

f (x) = (x + 2)^{2} (x + 1)

(- \frac{5}{3}, - \frac{2}{27})

Solution steps

f^{''} (x) = 2 (3 x + 5)

Find intervals:

Concave Downward

: - \infty < x < - \frac{5}{3},

Concave Upward

: - \frac{5}{3} < x < \infty

Plug

x = - \frac{5}{3}

into

(x + 2)^{2} (x + 1) : - \frac{2}{27}

(- \frac{5}{3}, - \frac{2}{27})

f (x) = \frac{1 + 9 x}{5 - 4 x}

(- 5.4) (7.2)

4 sin (x)

f (x) = 2 x^{3}

What is the inflection f(x)=(x+2)^2(x+1) ?
The inflection f(x)=(x+2)^2(x+1) is (-5/3 ,-2/27)