What is the domain of f(x)=sqrt(x^2+4)+4x-4 ?

The domain of f(x)=sqrt(x^2+4)+4x-4 is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+4)+4x-4

domain

f (x) = x^{2} + 4 + 4 x - 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} + 1, x \geq 0

ln (e + \frac{1}{x})

f (x) = \frac{2}{64 - x ^{2}}

f (x) = 2 x^{3} - 2

f (x) = 9 x - 2

What is the domain of f(x)=sqrt(x^2+4)+4x-4 ?
The domain of f(x)=sqrt(x^2+4)+4x-4 is -infinity <x<infinity