What is the domain of f(x)=(4x^2+1)/(2x) ?

The domain of f(x)=(4x^2+1)/(2x) is x 0

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domain of f(x)=(4x^2+1)/(2x)

domain

f (x) = \frac{4 x ^{2} + 1}{2 x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

(3, 3), (2, - 2)

f (x) = 3 x - ln (3 x)

\frac{x ^{2} - 16}{x ^{2} - 1}

f (x) = \frac{x}{x ^{2} + 4}

f (x) = \frac{x ^{2} - 5 x + 10}{x + 5}

What is the domain of f(x)=(4x^2+1)/(2x) ?
The domain of f(x)=(4x^2+1)/(2x) is x<0\lor x>0