What is the inverse of f(x)= 4/((x-3)^2) ?

The inverse of f(x)= 4/((x-3)^2) is (2sqrt(x))/x+3,-(2sqrt(x))/x+3

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inverse of f(x)= 4/((x-3)^2)

inverse

f (x) = \frac{4}{( x - 3 ) ^{2}}

\frac{2 x}{x} + 3, - \frac{2 x}{x} + 3

Solution steps

y = \frac{4}{( x - 3 ) ^{2}}

Replace

x

with

y

x = \frac{4}{( y - 3 ) ^{2}}

Solve for

y, x = \frac{4}{( y - 3 ) ^{2}}

\frac{2 x}{x} + 3, - \frac{2 x}{x} + 3

f (x) = \frac{x ^{3} + 1}{x}

f (x) = \frac{10}{x ^{2} - 25}

(- 9.4) (- 2.7)

f (x) = 2 + 5 x

f (x) = 2 e^{2 x + 1}

What is the inverse of f(x)= 4/((x-3)^2) ?
The inverse of f(x)= 4/((x-3)^2) is (2sqrt(x))/x+3,-(2sqrt(x))/x+3