What is the asymptotes of f(x)=(2e^x)/(e^x-5) ?

The asymptotes of f(x)=(2e^x)/(e^x-5) is Vertical: x=ln(5),Horizontal: y=2,y=0

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asymptotes of f(x)=(2e^x)/(e^x-5)

asymptotes

f (x) = \frac{2 e ^{x}}{e ^{x} - 5}

Vertical : x = ln (5), Horizontal : y = 2, y = 0

Solution steps

Vertical asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} : x = ln (5)

Horizontal Asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} : y = 2, y = 0

Slant Asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} :

None

Vertical : x = ln (5), Horizontal : y = 2, y = 0

f (x) = lo g_{2} (x^{2} - 7 \cdot x + 12)

f (x) = x^{4} - 8 x^{3}

f (x) = 2 x^{2} - 12 x + 18

f (x) = - 3 x^{2} + 4 x - 3

\frac{x ^{2} - 81}{x ^{3} + 7 x ^{2} - 18 x}

What is the asymptotes of f(x)=(2e^x)/(e^x-5) ?
The asymptotes of f(x)=(2e^x)/(e^x-5) is Vertical: x=ln(5),Horizontal: y=2,y=0