What is the inverse of f(x)=4+sqrt(3x-2) ?

The inverse of f(x)=4+sqrt(3x-2) is (x^2-8x+18)/3

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inverse of f(x)=4+sqrt(3x-2)

inverse

f (x) = 4 + 3 x - 2

\frac{x ^{2} - 8 x + 18}{3}

Solution steps

y = 4 + 3 x - 2

Replace

x

with

y

x = 4 + 3 y - 2

Solve for

y, x = 4 + 3 y - 2

\frac{x ^{2} - 8 x + 18}{3}

x^{3} - 11 x^{2} + 39 x - 47

f (x) = 2 x + 2

f (x) = x^{2}

(1.5) (9.3)

f (x) = - \frac{1}{2} x + 3

What is the inverse of f(x)=4+sqrt(3x-2) ?
The inverse of f(x)=4+sqrt(3x-2) is (x^2-8x+18)/3