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Popular >

distance (4,2),(0,4)

Solution

distance

(4, 2), (0, 4)

Solution

25

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, 2)

and

(0, 4)

is

= (0 - 4)^{2} + (4 - 2)^{2}

Simplify

= 25

Popular Examples

domain of (sqrt(5x))/(7x-2)domain

\frac{5 x}{7 x - 2}

critical (x^2)/(x^2+3)critical points

\frac{x ^{2}}{x ^{2} + 3}

inverse of f(x)=6x^4 inverse

f (x) = 6 x^{4}

inverse of f(x)= 1/2 (x-1)^2-5 inverse

f (x) = \frac{1}{2} (x - 1)^{2} - 5

line (1,8),(-2,5)line

(1, 8), (- 2, 5)

Frequently Asked Questions (FAQ)

What is the distance (4,2),(0,4) ?
The distance (4,2),(0,4) is 2sqrt(5)