What is the domain of y=arctan((x-1)/(x+1)) ?

The domain of y=arctan((x-1)/(x+1)) is x -1

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domain of y=arctan((x-1)/(x+1))

domain

y = arctan (\frac{x - 1}{x + 1})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

3 x - 2 y = 5

y = 5 x + 11, (- 1, 6)

f (x) = \frac{x ^{3} \cdot e ^{2}}{x \cdot ln ( x ) \cdot e}

\frac{x + 4}{x - 4}

f (x) = \frac{- 1 - x}{3}

What is the domain of y=arctan((x-1)/(x+1)) ?
The domain of y=arctan((x-1)/(x+1)) is x<-1\lor x>-1