What is the domain of (sqrt(1-x))(sqrt(25-x^2)) ?

The domain of (sqrt(1-x))(sqrt(25-x^2)) is -5<= x<= 1

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domain of (sqrt(1-x))(sqrt(25-x^2))

domain

(1 - x) (25 - x^{2})

- 5 \leq x \leq 1

Interval Notation

[- 5, 1]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 1

The function domain

- 5 \leq x \leq 1

2 - \frac{x}{x - 2}

f (x) = x^{2} + 3 x

(- 7, 6), (3, 8)

f (x) = - 9 x^{2} + 2 x^{3}

y = \frac{x - 7}{x + 5}

What is the domain of (sqrt(1-x))(sqrt(25-x^2)) ?
The domain of (sqrt(1-x))(sqrt(25-x^2)) is -5<= x<= 1