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Popular >

range of 2x^2-5

Solution

range

2 x^{2} - 5

Solution

f (x) \geq - 5

+1

Interval Notation

[- 5, \infty)

Solution steps

Vertex of

2 x^{2} - 5 :

Minimum

(0, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (0, - 5)

f (x) \geq - 5

Popular Examples

asymptotes of f(x)=(-x^2+4x-3)/(2-x)asymptotes

f (x) = \frac{- x ^{2} + 4 x - 3}{2 - x}

asymptotes of f(x)=xe^{-3x}asymptotes

f (x) = x e^{- 3 x}

inflection f(x)=4x^3-48x-7 inflection points

f (x) = 4 x^{3} - 48 x - 7

domain of (sqrt(2x))(sqrt(-3x+6))domain

(2 x) (- 3 x + 6)

y = (x + 3)^{2}

Frequently Asked Questions (FAQ)

What is the range of 2x^2-5 ?
The range of 2x^2-5 is f(x)>=-5