What is the extreme f(x)=xsqrt(x+3) ?

The extreme f(x)=xsqrt(x+3) is Maximum(-3,0),Minimum(-2,-2)

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extreme f(x)=xsqrt(x+3)

extreme points

f (x) = x x + 3

Maximum (- 3, 0), Minimum (- 2, - 2)

Solution steps

f^{'} (x) = \frac{3 x + 6}{2 x + 3}

Find intervals:

Decreasing

: - 3 < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 3

into

x x + 3 : 0

Maximum (- 3, 0)

Plug

x = - 2

into

x x + 3 : - 2

Minimum (- 2, - 2)

Maximum (- 3, 0), Minimum (- 2, - 2)

f (x) = \frac{3 x}{8 + x}

f (x) = x^{2} - 8 x - 15

(- 1, 8), (4, 8)

f (x) = (x - 7)^{2} - 11

5 - (3 y + 2 x) = 8 (x - y)

What is the extreme f(x)=xsqrt(x+3) ?
The extreme f(x)=xsqrt(x+3) is Maximum(-3,0),Minimum(-2,-2)