What is the inverse of f(x)=\sqrt[3]{(-x-3)/2} ?

The inverse of f(x)=\sqrt[3]{(-x-3)/2} is -2x^3-3

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inverse of f(x)=\sqrt[3]{(-x-3)/2}

inverse

- 2 x^{3} - 3

Solution steps

Replace

x

with

y

Solve for

- 2 x^{3} - 3

f (x) = \frac{- 16 + n}{4}

f (x) = - x - 7

y = \frac{3}{4} x - 3

y - x = - 5

f (x) = arccos (\frac{2 x + 1}{x - 3})

What is the inverse of f(x)=\sqrt[3]{(-x-3)/2} ?
The inverse of f(x)=\sqrt[3]{(-x-3)/2} is -2x^3-3