What is the inverse of y=-2(x-3)^2+1 ?

The inverse of y=-2(x-3)^2+1 is sqrt(-(x-1)/2)+3,-sqrt(-(x-1)/2)+3

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inverse of y=-2(x-3)^2+1

inverse

y = - 2 (x - 3)^{2} + 1

- \frac{x - 1}{2} + 3, - - \frac{x - 1}{2} + 3

Solution steps

y = - 2 (x - 3)^{2} + 1

Replace

x

with

y

x = - 2 (y - 3)^{2} + 1

Solve for

y, x = - 2 (y - 3)^{2} + 1

- \frac{x - 1}{2} + 3, - - \frac{x - 1}{2} + 3

y = x^{2} + 4 x + 4

f (x) = x

f (x) = \frac{1 - 4 x}{2 x + 9}

f (x) = 4 + 8 x - 5 x^{2}

f (x) = x + 9 - 2

What is the inverse of y=-2(x-3)^2+1 ?
The inverse of y=-2(x-3)^2+1 is sqrt(-(x-1)/2)+3,-sqrt(-(x-1)/2)+3