What is the critical y=x^{9/2}-7x^2 ?

The critical y=x^{9/2}-7x^2 is x=0,x=(784/81)^{1/5}

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critical y=x^{9/2}-7x^2

critical points

y = x^{\frac{9}{2}} - 7 x^{2}

x = 0, x = (\frac{784}{81})^{\frac{1}{5}}

Solution steps

x^{\frac{9}{2}} - 7 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = (\frac{784}{81})^{\frac{1}{5}}

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{9}{2}} - 7 x^{2} : x \geq 0

All critical points are in domain

x = 0, x = (\frac{784}{81})^{\frac{1}{5}}

f (x) = \frac{1}{1 + x ^{2}}

f (x) = \frac{x}{( x - 2 ) ( x + 3 )}

f (x) = a (1 - \frac{1}{1 - 2 ^{- x}})

f (x) = - x^{3} + 9 x^{2} - 52

\frac{1}{x ^{2}}

What is the critical y=x^{9/2}-7x^2 ?
The critical y=x^{9/2}-7x^2 is x=0,x=(784/81)^{1/5}