What is the domain of f(x)=\sqrt[4]{x^2-5x} ?

The domain of f(x)=\sqrt[4]{x^2-5x} is x = 5

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domain of f(x)=\sqrt[4]{x^2-5x}

domain

x \leq 0 or x \geq 5

Interval Notation

(- \infty, 0] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

The function domain

x \leq 0 or x \geq 5

f (x) = 4 x^{2} + 1

f (x) = \frac{1}{2} x^{2} - x

f (x) = \frac{x}{( x ^{3} - 1 )}

f (x) = \frac{- 3}{2 x + 5}

f (x) = x 49 - x^{2}

What is the domain of f(x)=\sqrt[4]{x^2-5x} ?
The domain of f(x)=\sqrt[4]{x^2-5x} is x<= 0\lor x>= 5