What is the domain of f(x)=sqrt(x^2-3) ?

The domain of f(x)=sqrt(x^2-3) is x = sqrt(3)

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domain of f(x)=sqrt(x^2-3)

domain

f (x) = x^{2} - 3

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = - \frac{3}{2} x - 1

9 x + 3 y = 3

5 x - 1

f (x) = 6 - 2^{- x + 1}

f (x) = \frac{x}{x - 5}

What is the domain of f(x)=sqrt(x^2-3) ?
The domain of f(x)=sqrt(x^2-3) is x<=-sqrt(3)\lor x>= sqrt(3)