What is the domain of f(x)=\sqrt[4]{x^2-7x} ?

The domain of f(x)=\sqrt[4]{x^2-7x} is x = 7

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domain of f(x)=\sqrt[4]{x^2-7x}

domain

x \leq 0 or x \geq 7

Interval Notation

(- \infty, 0] \cup [7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 7

The function domain

x \leq 0 or x \geq 7

f (x) = 5 x = 40

\frac{x ^{2}}{x ^{2} - 9}

x^{3} - 6 x^{2} + 6 x - 5

f (x) = \frac{x - 5}{x ^{2} + 2}

y = x^{2} - 4 x + 4

What is the domain of f(x)=\sqrt[4]{x^2-7x} ?
The domain of f(x)=\sqrt[4]{x^2-7x} is x<= 0\lor x>= 7