What is the domain of f(x)=sqrt(6x+1) ?

The domain of f(x)=sqrt(6x+1) is x>=-1/6

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domain of f(x)=sqrt(6x+1)

domain

f (x) = 6 x + 1

x \geq - \frac{1}{6}

Interval Notation

[- \frac{1}{6}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{6}

The function domain

x \geq - \frac{1}{6}

(8, 6), (0, - 3)

f (x) = \frac{2 x + 1}{2}

f (x) = \frac{x ^{2} - 3}{x ^{2} - 1}

(2, 20), (3, 40)

f (x) = x^{3} + x^{2}

What is the domain of f(x)=sqrt(6x+1) ?
The domain of f(x)=sqrt(6x+1) is x>=-1/6