What is the inverse of f(x)= 1/4 x^2-1 ?

The inverse of f(x)= 1/4 x^2-1 is 2sqrt(x+1),-2sqrt(x+1)

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inverse of f(x)= 1/4 x^2-1

inverse

f (x) = \frac{1}{4} x^{2} - 1

2 x + 1, - 2 x + 1

Solution steps

y = \frac{1}{4} x^{2} - 1

Replace

x

with

y

x = \frac{1}{4} y^{2} - 1

Solve for

y, x = \frac{1}{4} y^{2} - 1

2 x + 1, - 2 x + 1

m = 8 b = 3

f (x) = 2 y = 4 x + 12

f (x) = 4 x^{\frac{1}{3}}

f (x) = ln (x - 3) + 4

y = - 2 x

What is the inverse of f(x)= 1/4 x^2-1 ?
The inverse of f(x)= 1/4 x^2-1 is 2sqrt(x+1),-2sqrt(x+1)