What is the range of (x+1)/(x-3) ?

The range of (x+1)/(x-3) is f(x) 1

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range of (x+1)/(x-3)

range

\frac{x + 1}{x - 3}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 1}{x - 3}

Inverse of

\frac{x + 1}{x - 3} : \frac{1 + 3 x}{x - 1}

\frac{1 + 3 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{1 + 3 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = 5 - 12 x

\frac{x ^{3}}{x ^{2} + 1}

f (x) = (x - 2)^{2} (x - 1)

y + 5 = \frac{1}{2} (x - 1)

f (x) = lo g_{2} (x)

What is the range of (x+1)/(x-3) ?
The range of (x+1)/(x-3) is f(x)<1\lor f(x)>1