What is the inverse of f(x)=3x^2-4 ?

The inverse of f(x)=3x^2-4 is sqrt((x+4)/3),-sqrt((x+4)/3)

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inverse of f(x)=3x^2-4

inverse

f (x) = 3 x^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

Solution steps

y = 3 x^{2} - 4

Replace

x

with

y

x = 3 y^{2} - 4

Solve for

y, x = 3 y^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

f (x) = \frac{3 x - 4}{2}

f (x) = (x + 3)^{\frac{3}{2}}

cos (2 x)

f (x) = \frac{2}{x}

What is the inverse of f(x)=3x^2-4 ?
The inverse of f(x)=3x^2-4 is sqrt((x+4)/3),-sqrt((x+4)/3)