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Popular >

midpoint (2,2),(2,-2)

Solution

midpoint

(2, 2), (2, - 2)

Solution

(2, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, 2), (x_{2}, y_{2}) = (2, - 2)

= (\frac{2 + 2}{2}, \frac{- 2 + 2}{2})

Refine

= (2, 0)

Popular Examples

inverse of h(x)= 3/4 x-2 inverse

h (x) = \frac{3}{4} x - 2

inverse of f(x)=-5/3 x-8 inverse

f (x) = - \frac{5}{3} x - 8

domain of f(x)=(x+3)^2-1 domain

f (x) = (x + 3)^{2} - 1

inverse of f(x)=(2x-7)/(3x)inverse

f (x) = \frac{2 x - 7}{3 x}

monotone x^2-6x+9 monotone intervals

x^{2} - 6 x + 9

Frequently Asked Questions (FAQ)

What is the midpoint (2,2),(2,-2) ?
The midpoint (2,2),(2,-2) is (2,0)