What is the domain of f(x)=sqrt(x^2-9) ?

The domain of f(x)=sqrt(x^2-9) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2-9)

domain

f (x) = x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

2 x - 3 y = 6

f (x) = (x - 1)^{2}, x \geq 1

\frac{9 x - 8}{3}

\frac{π}{2}

2.75 x + 6.5 y = 1762

What is the domain of f(x)=sqrt(x^2-9) ?
The domain of f(x)=sqrt(x^2-9) is x<=-3\lor x>= 3