What is the inverse of f(x)=((x-2))/(x+2) ?

The inverse of f(x)=((x-2))/(x+2) is (-2-2x)/(x-1)

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inverse of f(x)=((x-2))/(x+2)

inverse

f (x) = \frac{( x - 2 )}{x + 2}

\frac{- 2 - 2 x}{x - 1}

Solution steps

y = \frac{x - 2}{x + 2}

Replace

x

with

y

x = \frac{y - 2}{y + 2}

Solve for

y, x = \frac{y - 2}{y + 2}

\frac{- 2 - 2 x}{x - 1}

\frac{8 - x ^{3}}{2 x ^{2}}

(4, - 4), (- 6, - 4)

f (x) = - 4 x^{2} - 2 x + 1

f (x) = x^{2} + 6 x + 5

f (x) = \frac{x}{x ^{3} - 8}

What is the inverse of f(x)=((x-2))/(x+2) ?
The inverse of f(x)=((x-2))/(x+2) is (-2-2x)/(x-1)