What is the monotone f(x)=(x+1)/(x-1) ?

The monotone f(x)=(x+1)/(x-1) is Decreasing:-infinity <x<1,Decreasing:1<x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

monotone f(x)=(x+1)/(x-1)

monotone intervals

f (x) = \frac{x + 1}{x - 1}

Decreasing : - \infty < x < 1, Decreasing : 1 < x < \infty

Solution steps

f^{'} (x) = - \frac{2}{( x - 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Decreasing : - \infty < x < 1, Decreasing : 1 < x < \infty

3 x^{2}

y - 2 = - 5 (x - 2)

f (x) = \frac{( 7 - 14 x )}{( 2 x - 3 )}

f (x) = \frac{7 x + 3}{3 x + 4}

f (x) = 0.5 x^{2} - 3 x + 4.5

What is the monotone f(x)=(x+1)/(x-1) ?
The monotone f(x)=(x+1)/(x-1) is Decreasing:-infinity <x<1,Decreasing:1<x<infinity