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Popular >

extreme t^2+2t-48

Solution

extreme points

t^{2} + 2 t - 48

Solution

Minimum (- 1, - 49)

Solution steps

f^{'} (t) = 2 t + 2

Find intervals:

Decreasing

: - \infty < t < - 1,

Increasing

: - 1 < t < \infty

Plug

t = - 1

into

t^{2} + 2 t - 48 : - 49

Minimum (- 1, - 49)

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f (x) = \frac{4 x - 3}{6 - 3 x}

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\frac{x - 2}{x + 3}

inflection f(x)=x^2(5-4x)^2 inflection points

f (x) = x^{2} (5 - 4 x)^{2}

Frequently Asked Questions (FAQ)

What is the extreme t^2+2t-48 ?
The extreme t^2+2t-48 is Minimum(-1,-49)