What is the asymptotes of f(x)=(x^2-1)/(x^4-16) ?

The asymptotes of f(x)=(x^2-1)/(x^4-16) is Vertical: x=-2,x=2,Horizontal: y=0

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asymptotes of f(x)=(x^2-1)/(x^4-16)

asymptotes

f (x) = \frac{x ^{2} - 1}{x ^{4} - 16}

Vertical : x = - 2, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 1}{x ^{4} - 16} : x = - 2, x = 2

Horizontal Asymptotes of

\frac{x ^{2} - 1}{x ^{4} - 16} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 1}{x ^{4} - 16} :

None

Vertical : x = - 2, x = 2, Horizontal : y = 0

f (x) = \frac{( sin ( x ) )}{x ^{2} + 1}

f (x) = \frac{y - 1}{y ^{2} - 3 y + 3}

(- 8, 0), (- 6, - 6)

\frac{x - 1}{3}

f (x) = 1.5

What is the asymptotes of f(x)=(x^2-1)/(x^4-16) ?
The asymptotes of f(x)=(x^2-1)/(x^4-16) is Vertical: x=-2,x=2,Horizontal: y=0