What is the inverse of f(x)=2+\sqrt[3]{x} ?

The inverse of f(x)=2+\sqrt[3]{x} is x^3-6x^2+12x-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2+\sqrt[3]{x}

inverse

f (x) = 2 + 3 x

x^{3} - 6 x^{2} + 12 x - 8

Solution steps

y = 2 + 3 x

Replace

x

with

y

x = 2 + 3 y

Solve for

y, x = 2 + 3 y

x^{3} - 6 x^{2} + 12 x - 8

f (x) = \frac{1}{\frac{1}{x}}

f (x) = lo g_{3} (4 x)

y = 3 x^{4} + 9

(\frac{1}{2})^{x}

f (x) = x - 2

What is the inverse of f(x)=2+\sqrt[3]{x} ?
The inverse of f(x)=2+\sqrt[3]{x} is x^3-6x^2+12x-8