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midpoint
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asymptotes of f(x)=(2x-2)/(x+2)asymptotes line Y=-X-1line periodicity of f(x)=sec(2x)periodicity parity \sqrt[3]{2x^2+1}parity critical f(x)=-3x^5+5x^3critical points
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-6),(-5,0) ?
The midpoint (-2,-6),(-5,0) is (-7/2 ,-3)