en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-2,5),(2,-3)

Solution

midpoint

(- 2, 5), (2, - 3)

Solution

(0, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, 5), (x_{2}, y_{2}) = (2, - 3)

= (\frac{2 - 2}{2}, \frac{- 3 + 5}{2})

Refine

= (0, 1)

Graph

Popular Examples

inverse of f(x)=10^x inverse

f (x) = 1 0^{x}

inverse of f(x)=tan(x)inverse

f (x) = tan (x)

inflection y=x^5-5x^4+8 inflection points

y = x^{5} - 5 x^{4} + 8

domain of sqrt(1-x^2)domain

1 - x^{2}

f(x)=-3x^2+3x-13

f (x) = - 3 x^{2} + 3 x - 13

Frequently Asked Questions (FAQ)

What is the midpoint (-2,5),(2,-3) ?
The midpoint (-2,5),(2,-3) is (0,1)