What is the inverse of f(x)=8x^2+4 ?

The inverse of f(x)=8x^2+4 is (sqrt(2)sqrt(x-4))/4 ,-(sqrt(2)sqrt(x-4))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=8x^2+4

inverse

f (x) = 8 x^{2} + 4

\frac{2 x - 4}{4}, - \frac{2 x - 4}{4}

Solution steps

y = 8 x^{2} + 4

Replace

x

with

y

x = 8 y^{2} + 4

Solve for

y, x = 8 y^{2} + 4

\frac{2 x - 4}{4}, - \frac{2 x - 4}{4}

(2) (0.1)

f (x) = \frac{x ^{2} - 3 x + 2}{x ^{2} + 1}

f (x) = \frac{9 - e ^{x^{2}}}{1 - e ^{9 - x^{2}}}

\frac{5}{x + 6}

f (x) = x^{2}

What is the inverse of f(x)=8x^2+4 ?
The inverse of f(x)=8x^2+4 is (sqrt(2)sqrt(x-4))/4 ,-(sqrt(2)sqrt(x-4))/4